Approximate weight (in gm) of $H_{2}$ $O_{2}$ in 560ml of 20 volumes $H_{2}$ $O_{2}$ solution is

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Solution

The correct option is B
34

20 volumes means 1 ml of $H_{2}$ $O_{2}$ gives 20ml of $O_{2}$

560ml of $H_{2}$ $O_{2}$ gives 11200ml of $O_{2}$

2 x34 gms of $H_{2}$ $O_{2}$ gives 22400ml of $O_{2}$

So, 34 gms of $H_{2}$ $O_{2}$ gives 11200ml of $O_{2}$

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