AQ || BS. If the statement is true then enter 1 else enter 0.

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Solution

Given: $P R ∥ B S$ , P is mid point of AB and Q is mid point of DR
$2 A D = A B$
$2 A D = A P + P B$
$2 A D = 2 A P$ (P is mid point of AB)
$A D = A P$
or A is mid point of PD
Now, In $△ D P R$ ,
A is mid point of PD and Q is mid point of QR. Thus, by converse of mid point theorem,
$A Q ∥ P R$
Since, $P R ∥ B S$
hence, $A Q ∥ P R ∥ B S$

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