Question

Aqueous copper sulphate solution (blue in colour) gives:
(a) a green precipitate with aqueous potassium fluoride, and
(b) a bright green solution with aqueous potassium chloride.

Then, the molecular formula of the given copper sulphate compound is:

• A. $\left[Cu\right(H_{2}O{)}_3\left(CN\right)]S{O}_4\cdot H_{2}O$
• B. $\left[Cu\right(H_{2}O{)}_{3}S{O}_4]\cdot H_{2}O$
• C. $\left[Cu\right(H_{2}O{)}_4]S{O}_4\cdot H_{2}O$
• D. none of these

Answer 1

The correct option is C $\left[Cu\right(H_{2}O{)}_4]S{O}_4\cdot H_{2}O$

Here, we can see that Aqueous copper sulphate solution is
aqueous $CuS{O}_4$ is $\left[Cu\right(H_{2}O{)}_4]S{O}_4\cdot H_{2}O$
(a)$\left[Cu\right(H_{2}O{)}_4^{2+}+KF\to \underset{greenppt}{[Cu{F}_4{]}^{2-}}$
(b)$\left[Cu\right(H_{2}O{)}_4{]}^{2+}+KCl\to \underset{lightgreen}{[CuC{l}_4{]}^{2-}}$