Aqueous $N a O H$ solution is labelled as $10$ % by weight mole fraction of the solute in it is:

0.05

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0.0476

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0.052

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0.52

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Solution

The correct option is C $0.0476$
Concentration of $N a O H = 10$ % $w / w$
Let there be $100 g$ of solution, then mass of $N a O H = 10 g$
Moles of $N a O H = \frac{10}{40} = 0.25 m o l e s$
Mass of water $= 100 - 10 = 90 g$
Moles of water $= \frac{90}{18} = 5 m o l e s$
Mole fraction of $N a O H = \frac{0.25}{5.25} = 0.0476$

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