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Interstitial Compounds

Aqueous solut...

Question

Aqueous solution of A can dissolve $A g B r$ forming a soluble complex B. A also reacts with aqueous ${A g N O}_{3}$ solution giving white ppt. C changing to black ppt D. (A) is the hypo solution $(N a_{2} S_{2} O_{3})$ , (B) is $N a_{3} [A g (S_{2} O_{3})_{2}]$ , (C) is $A g_{2} S_{2} O_{3}$ and (D) is $A g_{2} S$ .
If true enter 1, else enter 0.

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Solution

The correct option is A 1
(A) is the hypo solution $(N a_{2} S_{2} O_{3})$ , (B) is $N a_{3} [A g (S_{2} O_{3})_{2}]$ , (C) is $A g_{2} S_{2} O_{3}$ and (D) is $A g_{2} S$ .
Silver bromide dissolves in hypo solution to form soluble complex which is $N a_{3} [A s (S_{2} O_{3})_{2}]$ .
$A g B r + 2 N a_{2} S_{2} O_{3} \to N a_{3} [A g (S_{2} O_{3})_{2}] + N a B r$ .
The black ppt is due to formation of $A g_{2} S$
$N a_{2} S_{2} O_{3} + 2 A g N O_{3} \to A g_{2} S_{2} O_{3} w h i t e w a t e r - -- \to A g_{2} S b l a c k + H_{2} S O_{4}$

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