Question

Aqueous solution of borax reacts with two mole of acids. This is because of:

• A. Formation of 2 mol of $B(OH{)}_3$ only
• B. Formation of 2 mol of $NaOH$ only
• C. Formation of 1 mol each of $B(OH{)}_3$ and $NaOH$
• D. Formation of 2 mole of $NaOH$ and 4 mole of $B(OH{)}_3$ of which only $NaOH$ reacts with acid

Answer 1

The correct option is D Formation of 2 mole of $NaOH$ and 4 mole of $B(OH{)}_3$ of which only $NaOH$ reacts with acid

$N{a}_2{B}_4{O}_7+7H_{2}O\to 4H_{3}B{O}_3+2NaOH$
$B(OH{)}_3$ or $H_{3}B{O}_3$ is an acid and does not react with acid.
Only $NaOH$ reacts with acid.
Hence, option d is correct.