Aqueous solution of chloride of an element A containing 1×10−3 moles after complete hydrolysis required 30 mL of 0.1 M AgNO3 solution to form AgCl. Element A is :
A
Al
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B
P
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C
Si
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D
S
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Solution
The correct option is C Al MCln(1×10−3)+3H2O→M(OH)n+nHCl(n×10−3) 30 mL of 0.1 M Ag+=3×10−3molAg+=n×10−3. n=3, thus element A is trivalent chloride AlCl3.