Aqueous solution of ${N a}_{2} {C O}_{3}$ is basic in nature due to

Hydrolysis of

N a^{+}

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Hydrolysis

{C O}_{3}^{2 -}

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Hydrolysis of both

N a^{+}

and

C O_{3}^{2 -}

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Hydrolysis of both

N a^{+}

and

{H C O}_{3}^{-}

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Solution

The correct option is A Hydrolysis of $N a^{+}$
When $N a_{2} C O_{3}$ is dissolved in water, due to hydrolysis. It produces strong base and weak acid. So, the solution is basic in nature.
$N a_{2} C O_{3} + 2 H_{2} O ⟶ 2 N a O H + H_{2} C O_{3}$
By hydrolysis of $N a^{+}$ , it produces $N a O H$ which is basic in nature.

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K_{a} (H C O_{3}^{-}) = 4.7 \times 10^{- 11}

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O H^{-} i o n

H C O_{3}^{-} + H_{2} O i o n i z a t i o n ⇋ C O_{3}^{2 -} + H_{2} O

H C O_{3}^{-} + H_{2} O i o n i z a t i o n ⇋ H_{2} C O_{3} + O H^{-}

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