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Decarboxylation Reaction of Alkanes

Aqueous solut...

Question

Aqueous solution of potassium propanoate is electrolysed. Possible organic products are:

n-Butane

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C_{2} H_{5} C O O C_{2} H_{5}

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C H_{3} - C H_{3}

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C H_{2} = C H_{2}

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Solution

The correct options are
A $C_{2} H_{5} C O O C_{2} H_{5}$
B n-Butane
C $C H_{3} - C H_{3}$
D $C H_{2} = C H_{2}$
Kolbe's electrolysis follows free radical mechanism and from this method alkane is formed by electrolysis of sodium salt of acid. In this reaction all given product formed in this reaction is $C_{2} H_{5} C O O^{∙}$ and $C_{2} H_{5}^{∙}$ is formed as intermediate.
These intermediate are unstable so they get converted into different stable organic compounds.

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