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Electronegativity

Aqueous solut...

Question

Aqueous solutions of two compounds $M_{1} - O - H$ and $M_{2} - O - H$ are prepared in two different beakers. If, the electronegativity of $M_{1} = 3.4$ , $M_{2} = 1.2$ , $O = 3.5$ and $H = 2.1$ , then the nature of two solutions will be respectively:

A

acidic, basic

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B

acidic, acidic

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C

basic, acidic

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D

basic, basic

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Solution

The correct option is A acidic, basic
According to Gallis if electronegativity of $M$ in a hydroxide $(M O H)$ is more than $1.7$ then it will be acidic in nature whereas it will be basic in nature if electronegativity is less than $1.7$ .
Hence, $M_{1} - O H$ will be acidic in nature and $M_{2} - O H$ will be basic in nature.

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