Question

Aqueous solutions of two compounds $M_1-O-H$ and $M_2-O-H$ are prepared in two different beakers. If, the electronegativity of $M_1=3.4$, $M_2=1.2$, $O=3.5$ and $H=2.1$, then the nature of two solutions will be respectively:

• A. acidic, basic
• B. acidic, acidic
• C. basic, acidic
• D. basic, basic

Answer 1

The correct option is A acidic, basic

According to Gallis if electronegativity of $M$ in a hydroxide $\left(MOH\right)$ is more than $1.7$ then it will be acidic in nature whereas it will be basic in nature if electronegativity is less than $1.7$.

Hence, $M_1-OH$ will be acidic in nature and $M_2-OH$ will be basic in nature.