are the roots of the quadratic equation $(x - 1)^{2}$ -121 = 0.

12, 12

No worries! We‘ve got your back. Try BYJU‘S free classes today!

11,-11

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-10,12

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is C -10,12
$(x - 1)^{2} - 121 = 0$

$(x - 1)^{2} = 121$

$(x - 1) = \sqrt{121}$

$(x - 1) = + 11 o r (x - 1) = - 11$

$x$ = 12 or $x$ = - 10

Suggest Corrections

Similar questions

(x - 1)^{2}

x + \frac{20}{x} - 12 = 0

x^{2} + 7 x + 12 = 0

x^{2} - 8 x - 12 = 0

α, β

x^{2} - 7 x + 12 = 0

- α, - β

Join BYJU'S Learning Program