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Byju's Answer
Standard XII
Physics
Examples
Area bounded ...
Question
Area bounded between curves
y
2
=
4
x
ā
4
and
y
=
x
ā
1
is
A
.
Then the value of
3
A
2
is
A
4.0
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B
04
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C
4
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D
4.00
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Solution
Intersection points of curves
y
2
=
4
x
−
4
and
y
=
x
−
1
:
(
x
−
1
)
2
=
4
x
−
4
⇒
x
2
−
6
x
+
5
=
0
⇒
x
=
1
,
5
The area between the curves
A
=
5
∫
1
[
√
4
x
−
4
−
(
x
−
1
)
]
d
x
⇒
A
=
[
4
(
x
−
1
)
3
/
2
3
−
x
2
2
+
x
]
5
1
⇒
A
=
32
3
−
25
2
+
5
+
1
2
−
1
⇒
A
=
8
3
∴
3
A
2
=
3
2
×
8
3
=
4
Suggest Corrections
0
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