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Question

Area bounded between curves y2=4x4 and y=x1 is A. Then the value of 3A2 is

A
04
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B
4.0
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C
4.00
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D
4
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Solution

Intersection points of curves y2=4x4 and y=x1:
(x1)2=4x4
x26x+5=0
x=1,5


The area between the curves
A=51[4x4(x1)]dx
A=[4(x1)3/23x22+x]51
A=323252+5+121
A=83
3A2=32×83=4

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