Question

Area bounded by curve $y=ksinx$ between $x=\pi$ and $x=2\pi$, is

• A. $2ksq.unit$
• B. $0$
• C. $\frac{k^2}{2}sq.unit$
  
• D. $ksq.unit$

Answer 1

The correct option is A $2ksq.unit$

Required area = $k{\int }_{\pi }^{2\pi }-sinxdx=k[cosx{]}_{\pi }^{2\pi }=2k$
Hence, area = 2k sq. unit.