Question

Area bounded by curve y = k sin x between x = $\pi$ and x = $x=2\pi$ is

• A. 2k sq. unit
• B. \N
• C. $\frac{k^2}{2}$ sq. unit
• D. k sq. unit

Answer 1

The correct option is A 2k sq. unit

Required area = $=k{\int }_{\pi }^{2\pi }sinxdx=k[-cosx{]}^2{x}_x=-2k$
Hence, area = 2k sq.unit.