Area bounded by lines $x - y + 1 = 0$ ; $3 x + 2 y - 12 = 0$ and x-axis is k.Find 2k

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Solution

The equation of first line is
x-y+1 $=$ 0
y $=$ x+1
We fill find values of y by putting different values of x
x=1
y=2
The equation of second line is
3x+2y-12 $=$ 0
2y $=$ 12-3x
y $= \frac{12 - 3 x}{2}$
We fill find values of y by putting different values of x
x=2
y=3
By drawing the graph from two tables of solution we see given lines meet at points (2,3)
Hence the solution is x $=$ 2,y $=$ 3
Area bounded by x-axis is $= \frac{1}{2} \times b a s e \times h e i g h t$
$= \frac{1}{2} \times 5 \times 3 =$ 7.5sq.unit

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Area bounded by lines x−y+1=0; 3x+2y−12=0 and x-axis is k.Find 2k

Area bounded by lines $x - y + 1 = 0$ ; $3 x + 2 y - 12 = 0$ and x-axis is k.Find 2k