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Byju's Answer
Standard XII
Mathematics
Equation of Normal at a Point (x,y) in Terms of f'(x)
Area bounded ...
Question
Area bounded by the curve
y
=
s
i
n
−
1
x
,
y
−
a
x
i
s
and
y
=
c
o
s
−
1
x
is equal to
A
(
2
+
√
2
)
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B
(
2
−
√
2
)
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C
(
1
+
√
2
)
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D
(
√
2
−
1
)
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Solution
The correct option is
D
(
√
2
−
1
)
Given,
y
=
sin
−
1
x
,
y
=
cos
−
1
x
,
y
−
a
x
i
s
⇒
sin
y
=
x
,
cos
y
=
x
⇒
sin
y
=
cos
y
⇒
tan
y
=
1
∴
y
=
tan
−
1
1
=
π
4
A
r
e
a
=
∫
π
4
0
cos
(
y
)
−
sin
(
y
)
d
y
=
∫
π
4
0
cos
(
y
)
d
y
−
∫
π
4
0
sin
(
y
)
d
y
=
1
√
2
−
(
−
1
√
2
+
1
)
=
√
2
−
1
Suggest Corrections
0
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