MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Property 7

Area bounded ...

Question

Area bounded by the curves $x = \sqrt{2 - y^{2}}$ and $| x | \geq | y |$ is

A

\frac{π}{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

π

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

\frac{3 π}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

2 π

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\frac{π}{2}$

Area $= \frac{1}{4}$ (area of circle) $= \frac{π}{2}$

Suggest Corrections

thumbs-up

0

Similar questions

Q. The area bounded by the curve

y = sin x

y = cos x

x = 0

x = \frac{π}{2}

Q. Area bounded between the curves

y = \sqrt{4 - x^{2}}

y^{2} = 3 | x |

Area bounded by curve y = k sin x between x = $π$ and x = $x = 2 π$ is

Q. Area of the region bounded by the x-axis and curves

y = t a n x (\frac{- π}{3} \leq x \leq \frac{π}{3})

y = c o t x (\frac{π}{6} \leq x \leq \frac{3 π}{2})

Q. The area bounded by the curve

y = sin 2 x, x = 0, x = π

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Property 7

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon