Question

Area bounded by y = x sin x and x - axis between x=0 and x = 2$\pi$ is [Roorkee 1981; RPET 1995]

• A. \N
• B. 2 $\pi$ sq. unit
• C. $\pi$ sq. unit
• D. 4 $\pi$ sq. unit

Answer 1

The correct option is D 4 $\pi$ sq. unit

Required area is $A_1+A_2={\int }_0^{x}ydx+\left|{\int }_x^{2}xydx\right|=4\pi sq.unit$