Area enclosed by the common tangents of circle x2+y2=4 and ellipse 3x2+5y2=15 is
A
4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
8
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
16
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
32
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C16 Equation of tangent y=mx±√5m2+3 ⇒mx−y±√5m2+3=0 Distance from (0,0)=2 ⇒2=√5m2+3√1+m2 Hence m=1,−1 So four tangents are : y=x±2√2y=−x±2√2 The required Area =4×12×2√2×2√2=16