Area enclosed by the curve y - f x defined parametrically as x -1- t 2-1- t 2- y -2 t -1- t 2 is equal toA- - sq- unitsB- -2 sq- unitC- 3 -4 sq - unitsD- 3 -2 sq- units

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Angle of Intersection of Two Curves

Area enclosed...

Question

Area enclosed by the curve y = f(x) defined parametrically as $x = \frac{1 - t^{2}}{1 + t^{2}}$ , $y = \frac{2 t}{1 + t^{2}}$ is equal to

π

sq. units

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\frac{π}{2}

sq. unit

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\frac{3 π}{4}

sq. units

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\frac{3 π}{2}

sq. units

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Similar questions

y = f (x)

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y = \sqrt{5 - x^{2}}

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y = f (x)

x = \frac{1 - t^{2}}{1 + t^{2}}

y = \frac{2 t}{1 + t^{2}}

t \in R

| y | = 1 - x^{2}

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Area bounded by the curves $y = e^{x}, y = l o g_{e} x$ and the lines x = 0, y = 0, y = 1 is

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