Area formed by the line :
$4 x - y - 8 = 0$
$2 x + y - 10 = 0$
$y = 0$
(in sq. unit)

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Solution

$4 x - y - 8 = 0$
$2 x + y - 10 = 0$

$y = 0$

Area of region $= \frac{1}{2} \times 1 \times 4 + \frac{1}{2} \times 2 \times 4$

$= \frac{1}{2} \times 3 \times 4 = 6 s q . u n i t s$

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