Question

Area (in sq. units) of the region outside $\frac{|x|}{2}+\frac{|y|}{3}=1$ and inside the ellipse $\frac{x^2}{4}+\frac{y^2}{9}=1$ is:

• A. $3(\pi -2)$
• B. $6(\pi -2)$
• C. $6(4-\pi )$
• D. $3(4-\pi )$

Answer 1

The correct option is B $6(\pi -2)$



$A=4(\frac{\pi ab}{4}-\frac{1}{2}\cdot 2\cdot 3)$

$A=\pi \cdot 2\cdot 3-12$

$A=6(\pi -2)$