Question 10

Area of a rectangle with length 4ab and breadth $6 b^{2}$ is
a) $24 a^{2} b^{2}$
b) $24 a b^{3}$
c) $24 a b^{2}$
d) $24 a b$

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Solution

b) $24 a b^{3}$
$\to$ We know that, area of a rectangle = Length $\times$ Breadth = $4 a b \times 6 b^{2}$
This is the product of two monomials.
$∴$ Area of rectangle $= (4 \times 6) a b \times b^{2} = 24 a b^{3}$

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Multiplication of Monomials

Standard VIII Mathematics

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Question 10 Area of a rectangle with length 4ab and breadth 6b2 is a) 24a2b2 b) 24ab3 c) 24ab2 d) 24ab

b) 24ab3 →​​​​​​​We know that, area of a rectangle = Length × Breadth = 4ab×6b2 This is the product of two monomials. ∴ Area of rectangle =(4×6)ab×b2=24ab3

Question 10

Area of a rectangle with length 4ab and breadth $6 b^{2}$ is
a) $24 a^{2} b^{2}$
b) $24 a b^{3}$
c) $24 a b^{2}$
d) $24 a b$

b) $24 a b^{3}$
$\to$ We know that, area of a rectangle = Length $\times$ Breadth = $4 a b \times 6 b^{2}$
This is the product of two monomials.
$∴$ Area of rectangle $= (4 \times 6) a b \times b^{2} = 24 a b^{3}$