Area of a regular octagon of side length -2 cm is -A- 2-2-1 cm 2B- 3-2-1 cm 2C- -2-1 cm 2D- 4-2-1 cm 2

The correct option is D 4( √2 + 1 ) cm2 Area of a regular octagon = 2(√(2)+1) a^2 a = √(2) Area = 4(√(2)+1) cm^2 ...

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Polygons(n>3)

Area of a reg...

Question

Area of a regular octagon of side length $\sqrt{2}$ cm is -

2 ( √2 + 1 ) cm²

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3 ( √2 + 1 )cm²

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( √2 + 1 )cm²

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4( √2 + 1 ) cm²

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If the area of a regular octagon is 8 $(\sqrt{2} + 1)$ $c m^{2}$ , the side length of octagon is -

In $Δ A B C, A B = 12 c m, ∠ A = 45^{\circ}, ∠ B = 30^{\circ} .$ Then the area of the triangle ABC is

2 \sqrt{3} - 1 c m^{2}

4 \sqrt{3} - 1 c m^{2}

6 \sqrt{3} - 1 c m^{2}

8 \sqrt{3} - 1 c m^{2}

Area of regular pentagon of side length 2 cm is -

= 3 \frac{\sqrt{3 a}}{2} s q

= 2 (1 + \sqrt{2}) a

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