Question

Area of a sector of a circle with radius r and angle with degrees measure $\theta$ is $\frac{\theta }{360}\times \pi r^m$
$m$ is

Answer 1

Area of whole ${360}^0$ of a circle = $\pi \times r^2$
Thus area of $\theta$ out of ${360}^0$ = $\frac{\theta }{360}\times \pi \times r^2$