Area of a sector of angle p (in degrees) of a circle with radius r is
× 2πr
× π
× 2π
Area of the sector of angle p =p360 × π r2
Figure shows a sector of a circle of radius r cm containing an angle θ ∘. The area of the sector is A cm2 and perimeter of the sector is 50 cm. Prove that
(i) θ=360π(25r−1)
(ii) A=25r−r2