Area of a sector of angle - with radius r is-

The correct option is A nbsp;[ 22/7 × r^2× θ]/360 Area of a sector of angle θ with radius r = [ 22/7 × r^2× θ]/360 ...

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Byju's Answer

Standard VIII

Mathematics

Area of Sector

Area of a sec...

Question

Area of a sector of angle $θ$ with radius r is:

$\frac{[\frac{22}{7} \times r^{2} \times θ]}{360}$

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$\frac{[\frac{22}{7} \times r \times θ]}{360}$

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$\frac{[\frac{22}{7} \times r^{2} \times θ]}{180}$

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$\frac{[\frac{22}{7} \times r \times θ]}{180}$

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Solution

The correct option is A
$\frac{[\frac{22}{7} \times r^{2} \times θ]}{360}$

Area of a sector of angle $θ$ with radius r
$= \frac{[\frac{22}{7} \times r^{2} \times θ]}{360}$

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Similar questions

Figure shows a sector of a circle of radius r cm containing an angle $θ^{\circ}$ . The area of the sector is A $c m^{2}$ and perimeter of the sector is 50 cm. Prove that

(i) $θ = \frac{360}{π} (\frac{25}{r} - 1)$

(ii) $A = 25 r - r^{2}$

The area of a sector of angle $θ^{\circ}$ of a circle with radius $R$ is

(a) $\frac{2 π R θ}{180}$

(b) $\frac{π R^{2} θ}{180}$

(d) $\frac{π R^{2} θ}{360}$

Q. Given figure shows a sector of a circle of radius r cm containing an angle

θ^{\circ}

. The area of the sector is

A c m^{2}

and the perimeter of the sector is 50 cm. Prove that

θ = \frac{360}{π} (\frac{25}{r} - 1)

If we have $∠ A B C$ as $θ$ , reflex $∠ A B C$ is equal to ________________.

Q. Prove:

{sec}^{4} θ - {tan}^{4} θ = 2 {sec}^{2} θ - 1

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Area of a sector of angle θ with radius r is:

The correct option is A [227×r2×θ]360 Area of a sector of angle θ with radius r =[227×r2×θ]360

Area of a sector of angle $θ$ with radius r is:

The correct option is A
$\frac{[\frac{22}{7} \times r^{2} \times θ]}{360}$

Area of a sector of angle $θ$ with radius r
$= \frac{[\frac{22}{7} \times r^{2} \times θ]}{360}$