Question

Area of a sector of circle of radius 12 cm and subtending an angle of 60${}^{\circ }$ at the centre is $c{m}^2$.

• A. $12\pi$
• B. $24\pi$
• C. $240\pi$
• D. $60\pi$

Answer 1

The correct option is B $24\pi$

We know that the area of a sector subtending an angle $\theta$ at the centre of a circle of radius $r$
$=\frac{\theta }{{360}^{\circ }}\times \pi r^2$

Given,
$r=12$ cm, $\theta ={60}^{\circ }$.
So, area of the sector $=\frac{60}{{360}^{\circ }}\times \pi \times 12\times 12=24\pi c{m}^2$