Question

Area of a square is $121d{m}^2$. Find its perimeter

Answer 1

Let $a$ be the edge of square.

Area of square $=121m^2$

$\Rightarrow a^2=121$

$\Rightarrow a=\sqrt{121}=11dm$

Therefore,

Perimeter of square $=4a=4\times 11=44dm$