MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Perpendicular from the Center to a Chord Bisects the Chord

Area of a tra...

Question

Area of a trapezium = $2 h \times (a + b)$
where h is the distance between the parallel sides a and b.

A

False

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

True

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A False

Suggest Corrections

thumbs-up

0

Similar questions

Q. Area of a trapezium =

2 h \times (a + b)

where h is the distance between the parallel sides a and b.

Q. If 'a' and 'b' are the parallel sides of the trapezium and 'h' is the distance between the parallel sides, then the area of trapezium is .

Q. The area of a trapezium is 262.5 sq cm and the perpendicular distance between its parallel sides is 15 cm. What is the sum of its parallel sides?

Q. The two parallel sides of a trapezium are

19.8 c m

7.2 c m

. If the area of the trapezium is

135 c m^{2}

, find the distance between its parallel sides.

Q. The difference between two parallel sides of a trapezium is 4 cm.The perpendicular distance between them is 19 cm.Find the area of the trapezium and find the length of parallel sides.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Circles and Their Chords - Theorem 3

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Perpendicular from the Center to a Chord Bisects the Chord

Standard IX Mathematics

Join BYJU'S Learning Program

CrossIcon