Question

# Area of a trapezium is $$160\ sq.cm$$. Lengths of parallel sides are in the ratio $$1:3$$. If smaller of the parallel sides is $$10\ cm$$ in length, then find the perpendicular distance between them.

Solution

## Given,Area of trapezium $$=160\ m^2$$The ratio of the length of its parallel sides $$=1:3$$Smaller parallel sides $$=10\ cm$$$$\therefore$$  Length of greater side $$=10\times 3=30\ cm$$Let the distance between them $$=h$$We know that, Area $$=\dfrac12\times$$ sum of parallel sides $$\times$$ height $$\Rightarrow 160=\dfrac12(30+10)h\\ \Rightarrow 160\times 2=40h\\ \Rightarrow h=\dfrac{320}{40}=8\ cm$$Mathematics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More