Question

Area of a trapezium is $160sq.cm$. Lengths of parallel sides are in the ratio $1:3$. If smaller of the parallel sides is $10cm$ in length, then find the perpendicular distance between them.

Answer 1

Given,

Area of trapezium $=160m^2$

The ratio of the length of its parallel sides $=1:3$

Smaller parallel sides $=10cm$

$\therefore$ Length of greater side $=10\times 3=30cm$

Let the distance between them $=h$

We know that,

Area $=\frac{1}{2}\times$ sum of parallel sides $\times$ height

$\Rightarrow 160=\frac{1}{2}(30+10)h\Rightarrow 160\times 2=40h\Rightarrow h=\frac{320}{40}=8cm$