Question

Area of a triangle is $6a^3{b}^2$ square units. What is the altitude of the triangle if the base of the triangle is 4ab units?

• A.
• B.
• C.
• D.

Answer 1

The correct option is D

Area of a triangle$=\frac{1}{2}\times \left(base\right)\times \left(altitude\right)$
Given that,
$6a^3{b}^2=\frac{1}{2}\times 4ab\times \left(altitude\right)$
Therefore,
$Altitude=\frac{2\times 6a^3{b}^2}{4ab}=3a^{2}b$ units.