1
Question
Area of a triangle whose vertices are (0, 0), (2, 3) , (5, 8) is _______ square units.
Area of a triangle whose vertices are (0, 0), (2, 3) , (5, 8) is _______ square units.
Open in App
Solution
The correct option is C 1/2
Area of a triangle with vertices (x1,y1) ; (x2,y2) and (x3,y3) is ∣∣x1(y2−y3)+x2(y3−y1)+x3(y1−y2)2∣∣
Hence, substituting the points (x1,y1)=(0,0) ; (x2,y2)=(2,3) and (x3,y3)=(5,8) in the area formula, we get
Area of triangle ABC =∣∣(0)(3−8)+(2)(8−0)+5(0−3)2∣∣=∣∣16−152∣∣=12units
Area of a triangle with vertices (x1,y1) ; (x2,y2) and (x3,y3) is ∣∣x1(y2−y3)+x2(y3−y1)+x3(y1−y2)2∣∣
Hence, substituting the points (x1,y1)=(0,0) ; (x2,y2)=(2,3) and (x3,y3)=(5,8) in the area formula, we get
Area of triangle ABC =∣∣(0)(3−8)+(2)(8−0)+5(0−3)2∣∣=∣∣16−152∣∣=12units
Suggest Corrections
0
Similar questions
View More
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
