Question

Area of circle in which a chord of length $2\sqrt{3}$ units, subtends angle ${120}^o$ at its center is-

• A. $\pi$ sq units
• B. $2\pi$ sq units
• C. $4\pi$ sq units
• D. None of these

Answer 1

Answer: (C)

$4\pi$ sq units

$OA=\frac{AC}{\sin {60}^0}=\frac{\sqrt{3}\times 2}{\sqrt{3}}=2$

$\therefore$ $r=2$ units

area $=\pi r^2=4\pi$ sq. units.