Question

Area of circle in which a chord of length $2\sqrt{3}units$, subtends angle ${120}^o$ at its centre is :

• A. $\pi squnits$
• B. $2\pi squnits$
• C. $4\pi squnits$
• D. $5\pi squnits$

Answer 1

Answer: (C)

$4\pi squnits$

R.E.F image

$\angle AOB={120}^{\circ }\therefore \angle AOM=\angle BOM={60}^{\circ }$

$AOSin{60}^{\circ }=AM=\frac{AB}{2}$

$\Rightarrow r\left(\sqrt{3}/2\right)=\sqrt{3}\Rightarrow r=2units$

$\therefore$ Area $=\pi r^2=4\pi (units{)}^2$