Question

Question 9

Area of $\Delta MNO$ in the figure is


(a) $\frac{1}{2}MN\times NO$
(b) $\frac{1}{2}NO\times MO$
(c) $\frac{1}{2}MN\times OQ$
(d) $\frac{1}{2}NO\times OQ$

Answer 1

We know that,
Area of triangle $=\frac{1}{2}\times Base\times Height$
$=\frac{1}{2}\times NO\times OQ$