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Any Point Equidistant from the End Points of a Segment Lies on the Perpendicular Bisector of the Segment

Area of recta...

Question

Area of rectangle $= 75 {c m}^{2}$ ,length is 15 cm then find breadth.

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Solution

$A r e a = b \times l$

$75 = b \times 15$

$b = \frac{75}{15} = 5 c m$

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= 15 {c m}^{2}

= 50 {c m}^{2}, l e n g t h = 10 c m

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Any Point Equidistant from the End Points of a Segment Lies on the Perpendicular Bisector

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