Area of square ABCD with A(1,0) and B(4,0) is ___ square units.

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Solution

Side of the square = AB = 4 - 1 = 3 units.

Area of the square $= (4 - 1) \times (4 - 1) = 9$

$= 9 s q . u n i t s$ .

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Side of the square = AB = 4 - 1 = 3 units. Area of the square =(4−1)×(4−1)=9 =9 sq.units.

Side of the square = AB = 4 - 1 = 3 units.

Area of the square $= (4 - 1) \times (4 - 1) = 9$

$= 9 s q . u n i t s$ .