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Byju's Answer
Standard XII
Mathematics
Properties of Determinants
Area of the ...
Question
Area of the
Δ
A
B
C
is equal to
A
x
y
c
o
s
(
θ
+
C
)
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B
(
x
+
y
)
s
i
n
θ
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C
x
y
s
i
n
(
θ
+
C
)
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D
1
2
x
y
s
i
n
(
θ
+
C
)
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Solution
The correct option is
B
x
y
s
i
n
(
θ
+
C
)
A
D
=
x
,
∠
A
D
C
=
180
(
C
+
θ
)
Area of
Δ
A
B
C
=
2
area
Δ
A
D
C
=
1
2
2
y
.
x
s
i
n
(
C
+
θ
)
=
x
y
s
i
n
(
C
+
θ
)
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0
Similar questions
Q.
In
Δ
A
B
C
, if
1
b
+
c
+
1
c
+
a
=
3
a
+
b
+
c
, then
∠
C
is equal to
Q.
In
Δ
A
B
C
, if
A
=
30
0
, b=2,
c
=
√
3
+
1
, then
C
−
B
2
is equal to
Q.
In
Δ
A
B
C
the sides opposite to angles
A
,
B
,
C
are denoted by
a
,
b
,
c
respectively.
The area of
Δ
A
B
C
is
a
2
−
(
b
−
c
)
2
.
Then
tan
A
is equal to?
Q.
Consider the point A(a, b + c), B(b, c + a) and (c, a + b) The area of
Δ
A
B
C
is
Q.
In a
Δ
A
B
C
,
2
a
c
sin
A
−
B
+
C
2
is equal to
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