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Question

Area of the ΔABC is equal to

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A
xycos(θ+C)
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B
(x+y)sinθ
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C
xysin(θ+C)
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D
12xysin(θ+C)
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Solution

The correct option is B xysin(θ+C)
AD=x,ADC=180(C+θ)
Area of ΔABC=2 area ΔADC=122y.xsin(C+θ)
=xysin(C+θ)

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