Question

Area of the given figure (in $c{m}^2$​) is ___. Given: AB=CD

• A. $21c{m}^2$
• B. $11c{m}^2$
• C. $41c{m}^2$
• D. $31c{m}^2$

Answer 1

The correct option is A

$21c{m}^2$

Area of trapezium AFED = Area of rectangle BCEF+ Area of triangle ABF + Area of triangle CDE.

Area of rectangle = $l\times b=3\times 6=18c{m}^2$

EF = BC = 6 cm;

AD = 8cm, $\therefore$ AB=CD=1cm

Area of triangle ABF = Area of triangle CDE = $\frac{1}{2}\times b\times h=\frac{1}{2}\times 1\times 3=1.5c{m}^2$

Area of trapezium =$18+1.5+1.5=21c{m}^2$