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Byju's Answer
Standard XII
Mathematics
Circum Radius
Area of the g...
Question
Area of the greatest rectangle that can be inscribed in the ellipse
x
2
a
2
+
y
2
b
2
=
1
is:
A
2
a
b
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B
a
b
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C
√
a
b
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D
a
b
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Solution
The correct option is
A
2
a
b
Area of rectangle
A
B
C
D
=
(
2
a
cos
θ
)
.
(
2
b
sin
θ
)
=
2
a
b
sin
2
θ
⇒
Area of greatest rectangle is equal to
2
a
b
, when
sin
2
θ
=
1
(maximum)
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