Area of the region bounded by rays $| x | + y = 1$ and X-axis is ___________.

\frac{1}{2}

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2

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1

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\frac{1}{4}

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Solution

The correct option is A $\frac{1}{2}$
given equation can also be written as $y = 1 - | x |$
point of intersection of the given line are $(1, 0) a n d (0, 1)$ and $(0, 0)$ will be the third vertices of the triangle formed
thus height and base of this triangle $= 1$
therefore Area = $1 \times 1 \times \frac{1}{2}$
Therefore answer is $A$

Suggest Corrections

Similar questions

| x | + y = 1

X -

List-I	List-II
1. Area of region bounded by $y = 2 x - x^{2}$ and $x -$ axis	a. $\frac{1}{3}$
2. Area of the region ${(x, y) : x^{2} \leq y \leq \| x \|}$	b. $\frac{1}{2}$
3. Area bounded by $y = x$ and $y = x^{3}$	c. $\frac{2}{3}$
4. Area bounded by $y = x \| x \|$ , $x$ -axis and $x = - 1, x = 1$	d. $\frac{4}{3}$