Area of the region bounded by y - e x - y - e - x and the line x -1 is A- e-1-nB- e -1- eC- e - e -1-2D- e-e-1-2

The correct option is D e +e^ 1 2 Area = ∫_0^1(e^x e^ x) dx = [e^x e^ x ]_0^1 = e + e^ x (1 + 1) = e +e^ 1 2 ...

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Question

Area of the region bounded by $y = e^{x}, y = e^{- x}$ and the line $x = 1$ is)

e + \frac{1}{e}

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e - \frac{1}{e}

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e + e^{- 1} + 2

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e + e^{- 1} - 2

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Area bounded by the curves $y = e^{x}, y = l o g_{e} x$ and the lines x = 0, y = 0, y = 1 is

x = 1, x = 2,

x (y - e^{x}) = sin x

2 x y = 2 sin x + x^{3}

y = e^{x}, y = e^{- x}

x = 1

y = e^{x}, y = e^{- x}

x = 1

y = (l n x)^{2}

x = e^{2}

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