Area of the region bounded by $y = | x |$ and $y = 1 - | x |$ is

\frac{1}{3}

sq. units

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1 sq. units

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\frac{1}{2}

sq. unit

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2 sq. units

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Solution

The correct option is B $\frac{1}{2}$ sq. unit
$y = | x |$ and $y = 1 - | x |$
So,the area of two triangles
$2 (a r e a o f △ A O C)$ $= 2 (\frac{1}{2} \times 1 \times \frac{1}{2}) = \frac{1}{2} s q u n i t s$

Suggest Corrections

Similar questions

y = | x |

y = - | x | + 2

\frac{3}{2}

y = cos x, x = 0,

x = π

y = x^{2} + 2

y = 2 | x | - cos π x

y = x e^{x}, y = x e^{- x}

x = 1

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