Area of the region bounded by $y = x - [x], y = [x]$ and $x$ -axis in $[$ 0,2 $]$ is:

\frac{5}{2}

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\frac{3}{2}

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Solution

The correct option is B 1
$y = x - [x], y = [x]$
The parallelogram Area= $2 (1 / 2 \times 1 \times 1)$
$= 1 s q u n i t s .$

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y = x^{2} - 3 x + 2

x -

x = 0, x = 3

y = x^{2} - x

=

y = | x - 2 |, x = 1, x = 3

Area of the region bounded by the curve y² = 2y - x and y-axis is:

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