Area of the region R-x-y-x2- y- x- is

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Area between x=g(y) and y Axis

Area of the r...

Question

Area of the region $R = {[(x, y) / x^{2} \leq y \leq x]}$ is

1 / 6

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 / 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 / 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

(x, y) ϵ R^{2} : y \geq R^{2} : y \geq \sqrt{| x + 3 |}, 5 y \leq (x + 9) \leq 15

List-I	List-II
1. Area of region bounded by $y = 2 x - x^{2}$ and $x -$ axis	a. $\frac{1}{3}$
2. Area of the region ${(x, y) : x^{2} \leq y \leq \| x \|}$	b. $\frac{1}{2}$
3. Area bounded by $y = x$ and $y = x^{3}$	c. $\frac{2}{3}$
4. Area bounded by $y = x \| x \|$ , $x$ -axis and $x = - 1, x = 1$	d. $\frac{4}{3}$

1234

{(x, y) : \frac{2}{1 + x^{2}} \geq y \geq x^{2}}

\begin{matrix} L i s t I & L i s t I I P . & A r e a b o u n d e d b y y = x | x |, x - a x i s, & 1. & \frac{10}{3} x = 1 a n d x = - 1 Q . & A r e a b o u n d e d b y x - y + 2, & 2. & \frac{64}{3} x = \sqrt{y} a n d x = 0 R . & A r e a e n c l o s e d b y y^{2} = x & 3. & \frac{2}{3} a n d y = | x | S . & A r e a b o u n d e d b y y^{2} = x & 4. & \frac{1}{6} y = 4 a n d x = 0 \end{matrix}

x^{2} + y^{2} + 6 x + 6 y + 2 = 0

3 x + 4 y + 8 = 0

Join BYJU'S Learning Program