Area of the triangle formed by $(1, - 4), (3, - 2)$ and $(- 3, 16)$ is

40

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48

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24

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12

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Solution

The correct option is C $24$
Area of triangle $= \frac{1}{2} [x_{1} (y_{2} - y_{3}) + x_{2} (y_{3} - y_{1}) + x_{3} (x_{1} - y_{2})]$

$= \frac{1}{2} [1 (- 2 - 16) + 3 (16 + 4) - 3 (- 4 + 2)]$

$= \frac{1}{2} [1 (- 18) + 3 (20) - 3 (- 2)]$

$= \frac{1}{2} (- 18 + 60 + 6)$

$= \frac{1}{2} (- 12 + 60)$

$= \frac{1}{2} (48) = 24$ Ans

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Similar questions

(1, 4), (3, - 2),

(- 3, 16)

Find the area of the triangle formed by joining the mid points of the sides of the triangle formed with coordinates A (-4, 3), B (2, 3) and C (4, 5).

12 \sqrt{2} c m

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