Question

Area of the triangle formed by the points P(-1.5, 3), Q(6, -2) and R(-3, 4) is 0.

• A. True
• B. False
• C. Ambiguous
• D. Data insufficient

Answer 1

The correct option is A True

We know that the area of the triangle whose vertices are $(x_1,y_1),(x_2,y_2),$ and $(x_3,y_3)$ is $\frac{1}{2}\left|x_1\right(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2\left)\right|$

Given $P(-1.5,3),Q(6,-2)$ and $R(-3,4)$
Therefore, area is given by
$=\frac{1}{2}\times \left[\right(-1.5\left)\right(-2-4)+6(4-3)+(-3\left)\right(3+2\left)\right]$
$=\frac{1}{2}\times (9+6-15)$
$=0$